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xD kaads saprot?

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Blackout	Feb 10 2007, 12:25 Post #1
Gimme More Group: weirdo Posts: 294 Joined: 4-November 05 From: Riga	atradu sekojoshu matemaatisku formulu internetaa: "to prove i know , the next line is 1113213211 31131211131221 Btw , interesting facts : If you think that the sequence is "non-mathematical", I derived this mathematical expression that gives the sequence... have fun! (D is a recursive function and t is the term number.) It's a lot easier if you think verbally, isn't it? By the way, % here is a certain non-integer remainder function. 2.1%0.1 would be 0, 2.1%0.2 would be 0.1, 2.1%0.3 would be 0 since 0.3 fits evenly into 2.1, etc.) If you really want conventional operators, you could define % with limits and modular arithmetic... D(t+1) = (sigma(K=1,LOG(D(t)10)-LOG(D(t)10)%1,((D(t)-D(t)%10^(LOG(D(t))- LOG(D(t))%1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)10) -LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t) 10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)* 10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10) %10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t) 10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)-( sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10 ^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)2(D(t) -D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))%1)+sigma(S=1, LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t) 10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10) -(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))% 10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+1)%((( sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))% 10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t) 10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t) 10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)2(D(t)-D(t)%10^(S -1))%10^S))%10^(K-1))%10^K/10^(K-1)100^(2sigma(N=1,K,(((D(t)-D(t)% 10^(LOG(D(t))-LOG(D(t))%1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1, LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10- (D(t)10-D(t)10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)* 10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)% 10^(R+1)))/10)%10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)% 1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)% 10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t) 10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1)) %10^S+.5)2(D(t)-D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t)) %1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10) %1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^ (R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10% 10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^ S+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^ (R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)-(sigma(R=1, LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/ 10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)2(D(t)-D(t)% 10^(S-1))%10^S))%10^(N-1))%10^N+1)%(((D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))% 1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)10)-LOG(D(t) 10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^ R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10- D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^ (S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10- D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)- (sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))% 10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)2 (D(t)-D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))%1)+ sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10 )%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^ R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)* 10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/ 10)%10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1, ABS((D(t)10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)% 10^(R+1)))/10)-(sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t) 10-D(t)10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1))) /10)%10^(S-1))%10^S+.5)2(D(t)-D(t)%10^(S-1))%10^S))%10^(N-1))%10^ N+.5))))/100)+(sigma(K=1,LOG(D(t)10)-LOG(D(t)10)%1,100^(1+sigma(N= 1,K-1,2((((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t) 10%10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)-( sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))% 10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(N-1))%10^N/10^(N- 1)+1)%(((sigma(R=1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10% 10^(R+1))%10^(R+2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)-(sigma(R= 1,LOG(D(t)10)-LOG(D(t)10)%1-1,ABS((D(t)10-D(t)10%10^(R+1))%10^(R+ 2)/10-(D(t)10-D(t)10%10^R)%10^(R+1)))/10)%10^(N-1))%10^N/10^(N-1)+ .5)))))/10)" Kaads vispaar saprot par ko iet runa, un kaa viss notiek? >___> --------------------

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Shumins	Feb 10 2007, 16:03 Post #2
Unregistered	Varbuut iesaakumaa tur kaut kas ir bijis... Bet iespeejams katrs idiots, kas to meegjinaajis paarkopeet un paarakstiit, nesaprotot rakstiito, to sabojaajis tiktaal, ka nekaa nesaprotu. Ar garaam formulaam ir taapat kaa gariem postiem, neviens nesaka, ka tur a vidu kaut kas ir. Taapat arii te, nekas nav atvasinaats, integreets, nekaadu rundu un lauku - domaaju katram pokemonam jau beidzot videni buutu jaazin. Buutu labaak kaadu augstaaku skolu amekleejushi, nevis ticeetu uber formulaam un spokiem + citplaneetieshiem + un burvestiibaam Es jau arii varu uzrakstiit uber apreekjinu: (2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+((2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30)))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+(2/3)+(48)-(3/9)/((22)+(2/2)+(37)+sin(120)+cos(30))+

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