xD kaads saprot? |
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xD kaads saprot? |
Blackout |
Feb 10 2007, 12:25
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#1
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Gimme More Group: weirdo Posts: 294 Joined: 4-November 05 From: Riga |
atradu sekojoshu matemaatisku formulu internetaa:
"to prove i know , the next line is 1113213211 31131211131221 Btw , interesting facts : If you think that the sequence is "non-mathematical", I derived this mathematical expression that gives the sequence... have fun! (D is a recursive function and t is the term number.) It's a lot easier if you think verbally, isn't it? By the way, % here is a certain non-integer remainder function. 2.1%0.1 would be 0, 2.1%0.2 would be 0.1, 2.1%0.3 would be 0 since 0.3 fits evenly into 2.1, etc.) If you really want conventional operators, you could define % with limits and modular arithmetic... D(t+1) = (sigma(K=1,LOG(D(t)*10)-LOG(D(t)*10)%1,((D(t)-D(t)%10^(LOG(D(t))- LOG(D(t))%1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)*10) -LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)* 10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)* 10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10) %10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t) *10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-( sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10 ^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)*2*(D(t) -D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))%1)+sigma(S=1, LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t) *10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10) -(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))% 10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+1)%((( sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))% 10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)* 10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)* 10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)*2*(D(t)-D(t)%10^(S -1))%10^S))%10^(K-1))%10^K/10^(K-1)*100^(2*sigma(N=1,K,(((D(t)-D(t)% 10^(LOG(D(t))-LOG(D(t))%1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1, LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10- (D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)* 10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)% 10^(R+1)))/10)%10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)% 1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)% 10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t) *10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1)) %10^S+.5)*2*(D(t)-D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t)) %1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10) %1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^ (R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10% 10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^ S+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^ (R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-(sigma(R=1, LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/ 10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)*2*(D(t)-D(t)% 10^(S-1))%10^S))%10^(N-1))%10^N+1)%(((D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))% 1)+sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)* 10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^ R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10- D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^ (S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10- D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)- (sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))% 10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(S-1))%10^S+.5)*2* (D(t)-D(t)%10^(S-1))%10^S))-(D(t)-D(t)%10^(LOG(D(t))-LOG(D(t))%1)+ sigma(S=1,LOG(D(t))-LOG(D(t))%1,(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10 )%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^ R)%10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)* 10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/ 10)%10^(S-1))%10^S+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1, ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)% 10^(R+1)))/10)-(sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)* 10-D(t)*10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1))) /10)%10^(S-1))%10^S+.5)*2*(D(t)-D(t)%10^(S-1))%10^S))%10^(N-1))%10^ N+.5))))/100)+(sigma(K=1,LOG(D(t)*10)-LOG(D(t)*10)%1,100^(1+sigma(N= 1,K-1,2*((((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)* 10%10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-( sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))% 10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(N-1))%10^N/10^(N- 1)+1)%(((sigma(R=1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10% 10^(R+1))%10^(R+2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)-(sigma(R= 1,LOG(D(t)*10)-LOG(D(t)*10)%1-1,ABS((D(t)*10-D(t)*10%10^(R+1))%10^(R+ 2)/10-(D(t)*10-D(t)*10%10^R)%10^(R+1)))/10)%10^(N-1))%10^N/10^(N-1)+ .5)))))/10)" Kaads vispaar saprot par ko iet runa, un kaa viss notiek? >___> -------------------- |
ETM |
Feb 10 2007, 13:46
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#2
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Very Old Fart Group: 40K Posts: 1177 Joined: 20-January 05 From: Man pajāt |
tu gribi lai tavai pamatskolas galvinjai paskaidro kas ir sigmas un logaritmiskaas funkcujas, vai arii veelies padaliities ar citiem pokemoniem shajaa KrUtAa FoRmUlAa?
-------------------- Because i can!
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Blackout |
Feb 10 2007, 14:04
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#3
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Gimme More Group: weirdo Posts: 294 Joined: 4-November 05 From: Riga |
absoluuti vienalga.
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Sigfa |
Feb 10 2007, 14:24
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#4
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Kami-sama Group: ALK Posts: 2738 Joined: 17-May 04 From: Starp pudelēm un četrām sienām |
augstaakaa matemaatika. Man gan vislielaako neizpratni izraisiija taa anglju valoda.
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Blackout |
Feb 10 2007, 14:25
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#5
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Gimme More Group: weirdo Posts: 294 Joined: 4-November 05 From: Riga |
atradu vienaa anglju forumaa, so yeah >_>
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Sigfa |
Feb 10 2007, 14:28
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#6
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Kami-sama Group: ALK Posts: 2738 Joined: 17-May 04 From: Starp pudelēm un četrām sienām |
ko tu domaa ar "anglju forumu" ? Vietu kur cilveeki maacaas anglju valodu?
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anti |
Feb 10 2007, 14:35
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#7
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Draņķītis Group: Jounin Posts: 922 Joined: 2-April 05 From: Latvija, Rīga |
-------------------- ALWAYS, I WANNA BE WITH YOU
AND MAKE BELIEVE WITH YOU AND LIVE IN HARMONY, HARMONY, OH LOVE ♫ |
Storm |
Feb 10 2007, 14:38
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#8
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Danshaku Group: Chuunin Posts: 290 Joined: 12-April 06 From: nya |
Interesanta formulinja jam man buutu piecas minuutes laika sadaam mulkiibaam uztaisiitu vienu prodzinju kas shito jautriibu izreekina. Ideja ir dabuut naakoso skaitli rindaa ja zinaams iepriekseejais tb. D(t+1)
-------------------- skills of a snail
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Blackout |
Feb 10 2007, 15:29
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#9
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Gimme More Group: weirdo Posts: 294 Joined: 4-November 05 From: Riga |
nee, forums ir taads, kur ir vienkaarshi cilveeki kas jau runaa angliski -.- vispaar apspriezhas. par jebko. no rules.
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Shumins |
Feb 10 2007, 16:03
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#10
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Unregistered |
Varbuut iesaakumaa tur kaut kas ir bijis...
Bet iespeejams katrs idiots, kas to meegjinaajis paarkopeet un paarakstiit, nesaprotot rakstiito, to sabojaajis tiktaal, ka nekaa nesaprotu. Ar garaam formulaam ir taapat kaa gariem postiem, neviens nesaka, ka tur a vidu kaut kas ir. Taapat arii te, nekas nav atvasinaats, integreets, nekaadu rundu un lauku - domaaju katram pokemonam jau beidzot videni buutu jaazin. Buutu labaak kaadu augstaaku skolu amekleejushi, nevis ticeetu uber formulaam un spokiem + citplaneetieshiem + un burvestiibaam Es jau arii varu uzrakstiit uber apreekjinu: (2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+((2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30)))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+(2/3)+(4*8)-(3/9)/((22)+(2/2)+(3*7)+sin(120)+cos(30))+ |
Storm |
Feb 10 2007, 16:39
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#11
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Danshaku Group: Chuunin Posts: 290 Joined: 12-April 06 From: nya |
Rezultaats : 896 XDD
Bet par teemu runaajot kaads sakars vipaar postot kko taadu? Bet varbuut butu jauka iedeja aizsaakt vienu interesantu topiku, kur kaads uzdod aakiigo uzdevumu un kurs tad pirmais izdomaa -------------------- skills of a snail
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Sigfa |
Feb 10 2007, 16:42
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#12
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Kami-sama Group: ALK Posts: 2738 Joined: 17-May 04 From: Starp pudelēm un četrām sienām |
tev to visu noteikti vajadzeeja rakstiit vienaa rindaa shumin... ar copy+paste tu savu domu nepieraadiisi.
Storm, ieliki excelii, lai izreekjina? EDIT: un tu kljuudijies, rezultaats ir 914.458029984138 . This post has been edited by Sigfa: Feb 10 2007, 16:55 |
Storm |
Feb 10 2007, 16:44
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#13
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Danshaku Group: Chuunin Posts: 290 Joined: 12-April 06 From: nya |
Nee, uzrakstiiju fikso progu XDD
Paarbaudiiju : excelis nemaz nenejm to briinumu pretii : 'formula to long' This post has been edited by Storm: Feb 10 2007, 16:48 -------------------- skills of a snail
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Shumins |
Feb 10 2007, 16:52
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#14
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Unregistered |
Arpraats, taksh tas nebija jaareekjina
ar copy+paste tu savu domu nepieraadiisi. Paskaties pirmo formulu vairaak un papeeti taas uzbuuvi, tas ir tas pats copy paste Garas formulas ne vienmeer briesmiigas, vienkaarshi daudz mazas saliktas kopaa, un taapat nekaada doma nav pirmaa formulaa, tas ir sviets ar kaadu mainiigo or constanti "t"... |
Sigfa |
Feb 10 2007, 17:03
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#15
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Kami-sama Group: ALK Posts: 2738 Joined: 17-May 04 From: Starp pudelēm un četrām sienām |
konstante nevar buut mainiiga.
storm, es gan gribeetu redzeet programmu, kura reekjina sigmas. EDIT: excelim ir arii taada forsha fiicha kaa macros, kurus var jauki izmantot garaam formulaam. This post has been edited by Sigfa: Feb 10 2007, 17:08 |
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